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How many tons of gravel aggregate per linear foot of absorption field are needed to maintain a 12-inch depth?

10 tons

12 tons

15 tons

To determine how many tons of gravel aggregate are needed per linear foot of an absorption field to maintain a 12-inch depth, it's essential to understand the volume calculations involved in the context of drainage systems, particularly for septic systems.

A depth of 12 inches translates to 1 foot. The amount of gravel required is dependent on both the dimensions of the absorption field and the specific properties of the gravel used, such as its density. In this case, the typical calculation assumes that a linear foot of absorption field filled with gravel at a depth of 12 inches would require approximately 15 tons. This is generally based on the standard density of gravel and the necessary volume to achieve proper drainage and support for the absorption system.

In practical terms, using 15 tons ensures that the absorption field has the capacity to handle wastewater efficiently, allowing for effective filtration and percolation into the surrounding soil. This amount provides not only the required depth but also accounts for the efficiency of the drainage system in a typical residential setup. Thus, the requirement of 15 tons for a 12-inch depth is consistent with common practices and guidelines in the field of residential construction and septic system installation.

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20 tons

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